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hey what's going on guys today I have 嘿今天我有什么事发生在我的家伙身上
something really really cool that I 我真的很酷
haven't seen anywhere else on YouTube 在YouTube上还没有其他地方出现过
this a couple of videos on it that are a 这 是上一对夫妇的影片 ，是
little old but I don't think it has as 有点老，但我不认为它有
much attention as it needs now I was 因为它现在需要我很多的关注
reading up about God's number now this 现在读这个关于上帝的号码
is the number that they gave to the 是他们给的数字
Rubik's Cube which is basically the 魔方这基本上就是魔方了
lowest number of moves that it would 最低的移动次数
take to put a Rubik's Cube back into its 拿把魔方放回
solved state from any given scramble 从任何给定的争夺中解决状态
which is 20 it takes just 20 moves from 这是20只需要20步
any given scrambled well at most 20 任何给定的扰动至多20
moves as the most efficient method to 移动作为最有效的方法
return any cube back into its solved 将任何立方体返回到它的解决方案
State now I found this to be very 国家现在我发现这是非常
interesting but of course it does take 有趣但当然它需要
more moves than that to return a cube 比返回多维数据集更多的动作
back into its solve state because we use 回到它的解决状态，因为我们使用
algorithms and those algorithms have a 算法和那些算法有一个
set number of moves so usually it would 设定的移动号码 ，这样通常会
be like well actually I don't know how 事实上我不知道如何
many moves it would take on average if 许多举措，如果平均需要
someone can let me know what that is let 有人可以让我知道那是什么
me know in the comment section below I'd 我知道在我下面的评论部分
really be interested in hearing about 真的有兴趣听到
that but I also found often doing a 但我也发现经常做一个
little bit of digging but it turns out 一点挖掘，但事实证明
these same people that figured out that 这些人都知道这一点
it takes 20 moves to bring a rubik's 它需要20步移动rubik's
cube back into its solved state from any 从任何立方体回到其解决状态
given scramble they also found an 给予争夺他们也发现了一个
algorithm that can be applied to the 算法， 可以应用于
rubik's cube on any angle on any 在任何角度的魔方
orientation of any scramble that we'll 任何争夺的方向，我们会
have the cube pass through it's solved 立方体通过它解决了
state they have some statistics 说明他们有一些统计数据
apparently it's not always the case it 显然它并非总是如此
might be like 75% of the time but the 可能是75％的时间，但是
cube will pass through its sold States 立方体将通过其销售的国家
whilst completing this algorithm so 而完成这个算法，
here's the algorithm here I actually 这里的算法在这里我居然
wrote it down so I had to put a grid 写下来，所以我不得不把网格
there so I could actually follow it 那么我可以真正遵循它
because it was kind of getting jumbled 因为它是一种 越来越混乱
up so we have L R to be L prime are you 所以我们有LR是L素是你
- f2 l b d u to be L prime R to be - L - f2 lbdu为L素数R为- L
prime D 2 u L prime V 2 u 2 R to be D 2 素数D 2u L素数V 2 u 2 R为D2
long algorithm 25 steps long but this 长算法25步长但是这个
this algo 这个算法
if applied to any scrambled cube on any 如果应用于任何扰乱的立方体
any axis or any orientation it will turn 任何轴或它将转向的任何方向
the cube back into its salt State so 立方体回到它的盐状态
let's give it a try so I got a got a 让我们试试看，结果我得到了一个
cube here I'm just going to give it a 立方体在这里， 我只是想给它一个
scramble because I don't have a 争夺，因为我没有一个
scrambler here right now and I think 现在，我认为这里是加扰器
that should be good enough all right so 这应该是足够好的 没事如此
let's just give this a try and see where 让我们试试看看在哪里
it ends up okay so let's try the 它结束了好吧，让我们试试吧
algorithm so let's do L R to be L prime 算法，让我们做LR为L素数
are you to f2l B D you to be L prime R 你是不是要BD成为L素R？
to be to L prime D 2 u L prime V to u 2 将L素数D 2 u L素数V变为u2
R to be D 2 and there you have it back R是D2，然后你回来了
into its old state i which i think is 到了旧式的 状态我我认为这是
rather interesting i've been messing 相当有趣，我一直在搞
around with this all night and I was 这一整晚，我都是
pretty surprised to see that it actually 很惊讶居然看到它
works that's actually a very rare case 这些作品实际上是非常罕见的情况
where you get right to the end of the 你在哪里得到正确的结局
algorithm usually it will pass through 算法通常会通过
it solve state at any given point on 它解决任何给定点上的状态
this algorithm so you could probably get 这个算法，所以你可能会得到
like 9 or 10 steps in usually it's 通常 是9或10步
around 14 15 that the puzzle will be 大约14 15这个难题将是
solved just to prove that this works I'm 解决只是为了证明这是我的作品
going to do it again so let's just do 要再做一次，让我们来做吧
another scramble here you can try this 另一个争夺你可以试试这个
at home you can try this one right now 在家里，你现在可以试试这个
if you have a Rubik's Cube then you can 如果你有魔方，那么你可以
give this a try yourself if it's already 如果已经存在，请尝试一下
scrambled and you can keep follow along 炒作，你可以继续沿着
with me and give this a try so let's 和我一起试试这个吧
just do a load of scrambling here ok so 只是做扰这里确定这样的负载
that looks pretty good so let's give 这看起来不错，所以让我们给
this another try 这是另一个尝试
so L 所以L
are to be L Prime 将是LPrime
are you to f2l B D you to be L prime are 你是不是BD，你是L总理
to and it's already passed through 它已经通过了
itself States you can see I've got B to 本身你可以看到我有B到
L prime D to you and the rest of the L素数D给你和剩下的
algorithm still to go so that is the 算法还是去，这样是
nature of the algorithm it's not like 算法的本质不是这样
any other algorithm where it will cycle 任何其他将循环的算法
the pieces the cube will pass through 立方体将通过的部分
it's solved state along this algorithm 它沿着这个算法解决了状态
now this they have some statistics with 现在这一点，他们有一些统计信息
them I haven't been able to find them 他们我一直无法找到他们
but basically if you get to the end of 但基本上如果你到了最后
the algorithm and the puzzle hasn't been 算法和难题一直没有
solved and all you had to do is go full 解决了，你所要做的就是全力以赴
circle and just continue with the 圈并继续与
algorithm from L all the way through and 算法从L一直到和
usually by the second time sometimes it 通常第二次有时它
happens you'll have to go through the 发生，你将不得不通过
third time but basically if you just 第三次，但基本上如果你只是
continue following this sequence the 继续按照这个顺序
cube will pass through its old state 立方体将通过它的旧状态
whilst performing this algorithm okay so 同时执行这个算法没关系
the the reason that it does this I'm not 它是这样做的原因我不是
entirely certain that basically this 完全肯定，基本上这个
algorithm has been built on statistics 算法已经建立在统计学上
statistically what is most likely to 统计最可能的是什么
bring two pieces together and this is 把两块拼在一起，这是
just based on all of the other 只是基于所有其他
algorithms that are out there floating 在那里漂浮的算法
around today all of the ll all of the 围绕今天所有的所有
PLL all of the f2l algorithms they all 锁定所有的f2l算法
come together and statistically with 与...一起统计
this sequence of notations you are more 这个符号序列更多
likely to get a to bring just a couple 可能会带来一对夫妇
of pieces together so it will bring two 拼在一起，所以它会带来两个
or four pieces together and the reason 或四件一起的原因
that it solves the puzzle is because at 它解决这个难题是因为在
some point in this process these 在这个过程中的一些点，这些
clusters of pieces will line up into 件的集群将排队到
their solid state which i think is 他们的固态，我认为是
rather interesting now I don't 现在我觉得很有意思
understand the entirety of it if you 了解它的全部，如果你
understand this more than I do then 那么比我更懂得这一点
please provide a detailed explanation 请提供详细的解释
below because I am NOT you know setup 下面是因为我不知道设置
for explaining this kind of stuff I 为了解释这种东西我
don't have my head kind of wrapped 没有我的头包裹
around it but anyways hope you guys 在它周围， 但无论如何希望你们
found this video informative give this a 发现这个视频资料给这个a
try for yourselves thank you guys 试试你自己，谢谢你们
watching 观看
and I'll see y'all next time 下次我会看到你们
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you 您