Welcome back.
In the last video, I showed you or hopefully, I did show
you that if I apply a force of F to a stationary, an
initially stationary object with mass m, and I apply that
force for distance d, that that force times distance, the
force times the distance that I'm pushing the object is
equal to 1/2 mv squared, where m is the mass of the object,
and v is the velocity of the object after pushing it for a
distance of d.
And we defined in that last video, we just
said this is work.
Force times distance by definition, is work.
And 1/2 mv squared, I said this is called kinetic energy.
And so, by definition, kinetic energy is the amount of work--
and I mean this is the definition right here.
It's the amount of work you need to put into an object or
apply to an object to get it from rest
to its current velocity.
So its velocity over here.
So let's just say I looked at an object here with mass m and
it was moving with the velocity v.
I would say well, this has a kinetic
energy of 1/2 mv squared.
And if the numbers are confusing you, let's say the
mass was-- I don't know.
Let's say this was a 5 kilogram object and it's
moving at 7 meters per second.
So I would say the kinetic energy of this object is going
to be 5-- 1/2 times the mass times 5 times 7 squared, times
velocity squared.
It's times 49.
So let's see.
1/2 times 49, that's a little under 25.
So it'll be approximately 125 Newton meters, which is
approximately-- and Newton meter is just
a joule-- 125 joules.
So this is if we actually put numbers in.
And so when we immediately know this, even if we didn't
know what happened, how did this object get to this speed?
Let's say we didn't know that someone else had applied a
force of m for a distance of d to this object, just by
calculating its kinetic energy as 125 joules, we immediately
know that that's the amount of work that was necessary.
And we don't know if this is exactly how this object got to
this velocity, but we know that that is the amount of
work that was necessary to accelerate the object to this
velocity of 7 meters per second.
So let's give another example.
And instead of this time just pushing something in a
horizontal direction and accelerating it, I'm going to
show you an example we're going to push something up,
but its velocity really isn't going to change.
Invert.
Let's say I have a different situation, and we're on this
planet, we're not in deep space.
And I have a mass of m and I were to apply a force.
So let's say the force that I apply is equal to mass times
the acceleration of gravity.
Mass times-- let's just call that gravity, right?
9.8 meters per second squared.
And I were to apply this force for a distance of d upwards.
Right?
Or instead of d, let's say h.
H for height.
So in this case, the force times the distance is equal
to-- well the force is mass times the acceleration of
gravity, right?
And remember, I'm pushing with the acceleration of gravity
upwards, while the acceleration of gravity is
pulling downwards.
So the force is mass times gravity, and I'm applying that
for a distance of h, right?
d is h.
So the force is this.
This is the force.
And then the distance I'm applying is going to be h.
And what's interesting is-- I mean if you want to think of
an exact situation, imagine an elevator that is already
moving because you would actually have to apply a force
slightly larger than the acceleration of gravity just
to get the object moving.
But let's say that the object is
already at constant velocity.
Let's say it's an elevator.
And it is just going up with a constant velocity.
And let's say the mass of the elevator is-- I don't know--
10 kilograms. And it moves up with a constant velocity.
It moves up 100 meters.
So we know that the work done by whatever was pulling on
this elevator, it probably was the tension in this wire that
was pulling up on the elevator, but we know that the
work done is the force necessary to pull up on it.
Well that's just going to be the force of gravity.
So we're assuming that the elevator's not
accelerating, right?
Because if the elevator was accelerating upwards, then the
force applied to it would be more than
the force of gravity.
And if the elevator was accelerating downwards, or if
it was slowing down upwards, then the force being applied
would be less than the acceleration of gravity.
But since the elevator is at a constant velocity moving up,
we know that the force pulling upwards is completely equal to
the force pulling downwards, right?
No net force.
Because gravity and this force are at the same level, so
there's no change in velocity.
I think I said that two times.
So we know that this upward force is equal to
the force of gravity.
At least in magnitude in the opposite direction.
So this is mg.
So what's m? m is 10 kilograms. Times the
acceleration of gravity.
Let's say that's 9.8 meters per second squared.
I'm not writing the units here, but we're all assuming
kilograms and meters per second squared.
And we're moving that for a distance of 100 meters.
So how much work was put into this elevator, or into this
object-- it doesn't have to be an elevator-- by whatever
force that was essentially pushing up on it or
pulling up on it?
And so, let's see.
This would be 98 times 100.
So it's 9,800 Newton meters or 9,800 joules.
After we've moved up 100 meters, notice there's no
change in velocity.
So the question is, where did all that work get
put into the object?
And the answer here is, is that the work got transferred
to something called potential energy.
And potential energy is defined as-- well,
gravitational potential energy.
We'll work with other types of potential energy later with
springs and things.
Potential energy is defined as mass times the force of
gravity times the height that the object is at.
And why is this called potential energy?
Because at this point, the energy-- work had to be put
into the object to get it to this-- in the case of
gravitational potential energy, work had to be put
into the object to get it to this height.
But the object now, it's not moving or anything, so it
doesn't have any kinetic energy.
But it now has a lot of potential to do work.
And what do I mean by potential to do work?
Well after I move an object up 100 meters into the air,
what's its potential to do work?
Well, I could just let go of it and have no outside force
other than gravity.
The gravity will still be there.
And because of gravity, the object will come down and be
at a very, very fast velocity when it lands.
And maybe I could apply this to some machine or something,
and this thing could do work.
And if that's a little confusing, let
me give you an example.
It all works together with our--
So let's say I have an object that is-- oh, I don't know-- a
1 kilogram object and we're on earth.
And let's say that is 10 meters above the ground.
So we know that its potential energy is equal to mass times
gravitational acceleration times height.
So mass is 1.
Let's just say gravitational acceleration is 10 meters per
second squared.
Times 10 meters per second squared.
Times 10 meters, which is the height.
So it's approximately equal to 100 Newton meters, which is
the same thing is 100 joules.
Fair enough.
And what do we know about this?
We know that it would take about 100-- or exactly-- 100
joules of work to get this object from the ground to this
point up here.
Now what we can do now is use our traditional kinematics
formulas to figure out, well, if I just let this object go,
how fast will it be when it hits the ground?
And we could do that, but what I'll show you is
even a faster way.
And this is where all of the work and energy
really becomes useful.
We have something called the law of conservation of energy.
It's that energy cannot be created or destroyed, it just
gets transferred from one form to another.
And there's some minor caveats to that.
But for our purposes, we'll just stick with that.
So in the situation where I just take the object and I let
go up here, up here it has a ton of potential energy.
And by the time it's down here, it has no potential
energy because the height becomes 0, right?
So here, potential energy is equal to 100 and here,
potential energy is equal to 0.
And so the natural question is-- I just told you the law
of conservation of energy, but if you look at this example,
all the potential energy just disappeared.
And it looks like I'm running out of time, but what I'll
show you in the next video is that that potential energy
gets converted into another type of energy.
And I think you might be able to guess what type that is
because this object is going to be moving really fast right
before it hits the ground.
I'll see you in the next video.